摘要
以独山传统工艺制作盐酸菜液为研究对象,运用涂布法分离纯化乳酸菌。采用生理生化试验和分子生物学法,鉴定菌株Y-12为棉籽糖乳球菌(Lactococcus raffinolactis)。运用比色法测定其对胆固醇和亚硝酸盐清除能力,该菌株对胆固醇和亚硝酸盐的降解率分别为78.15%和75.17%。对菌株Y-12进行耐酸、耐盐和耐胆盐试验研究,结果表明,菌株Y-12在pH值为≥2.5的酸性环境中能正常生长,能够耐受5%Na Cl和0.3%胆盐。
Lactic acid bacteria were separated and purified from pickled vegetable produced by Dushan traditional fermentation process by spread plate method. Strain Y-12 was identified as Lactococcus raffinolactis by physiological biochemical tests and molecular biology method. The scavenging activity of the strain Y-12 on cholesterol and nitrite was determined by colorimetric method. The degradation rate of strain Y-12 on cholesterol and nitrite were 78.15% and 75.17%, respectively. The results of acid resistance, salt resistance and bile salt resistance tests showed that strain Y-12 was able to grow in acidic environment （pH ≥2.5）, and could tolerate 5% NaCl and 0.3% bile salts.
出处
《中国酿造》
CAS
北大核心
2017年第7期37-41,共5页
China Brewing
基金
贵州省教育厅自然科学研究重点项目(黔教合KY[2014]286)
贵州省科学技术联合基金项目(黔科合LH字[2014]7418)
关键词
棉籽糖乳球菌
胆固醇
亚硝酸盐
乳酸菌
Lactococcus raftinolactis
cholesterol
nitrite
lactic acid bacteria
