摘要
研究了碱性溶液中甲醇-联吡定钌(Ⅱ)[Ru(bpy)_3^(2+)]的电致化学发光行为.在玻碳电极上甲醇于+1.28V(vs.Ag/AgCl)处被氧化为甲氧基离子(CH_3O·),该自由基离子发生歧化反应,生成激发态的甲醛(HCHO^(?)),发出波长为545nm的光.另一方面当体系含有少量的Ru(bpy)_3^(2+)时会得到较强的发光信号,发光波长为608nm,该发光起因于在甲醇的氧化电位下,Ru(bpy)_3^(2+)被氧化成Ru(bpy)_3^(3+),CH_3O·与Ru(bpy)_3^(3+)反应,生成激发态的Ru(bpy)_3_(2+)(?)而发光.
The luminescent electrooxidation of methanol in tris(2,2' - bipyridine) ruthenium (Ⅱ) [Ru(bpy)32+ ] alkaline solution on a glassy carbon electrode has been studied. At the potential of +1. 28V (vs. Ag/AgCl), methanol was oxidized to methoxyl radical, and the excited formaldehyde was generated by a disprotionation reaction of the methoxyl radical to yield light emission with the wavelength of 545 nm. Brighter light emission could be found if small amount of Ru(bpy)32+ was added. The luminescent wavelength was 608 nm because Ru(bpy)32+ was oxidized to Ru(bpy)33+ and reacted with methoxyl radical to produce the excited state of Ru(bpy)32+* .
出处
《化学学报》
SCIE
CAS
CSCD
北大核心
1998年第3期238-243,共6页
Acta Chimica Sinica
基金
博士后科学基金
关键词
电致化学发光
甲醇
联吡啶钌
ECL
electrochemiluminescence,methanol,tris(2,2' -bipyridine) ruthenium(Ⅱ)
