摘要
η~5-RO_2CC_5H_4(CO)_3MNa(1)与R^1HgCl(2,R^1=Me,Et,Ph)可发生一种非预期的金属键形成反应,生成[η~5-RO_2CC_5H_4(CO)_3M]_2Hg(3a—3f)(R=Me,Et;M=Cr,Mo,W)。对反应中间物η~5EtQ_2CC_5H_4(CO)_3MoHgPh的研究表明:反应是按缩合及对称化两步机理进行的。3e(R=Et,M=Mo)属三斜晶系,空间群P-1。a=0.6333(1),b=0.7712(1),c=1.4204(4)nm;a=77.31(1),β=74.51(2),γ=68.72(1)°;V=0.61714nm^3;Z=1;D_x=2.246g/cm^3;R=0.044.
The metal—metal bond formation reaction took place between η~5-RO_2CC_5H_4(CO)_3 MNa (1) and R^1 HgCl (2, R^1 =Me, Et, Ph) to give [RO_2CC_5H_4(CO)_3M]_2 Hg (3a—3f) R =Me, Et; M=Cr, Mo, W), unexpectedly. The study on an intermediate η~5-EtO_2CC_5H_4 (CO)_3MoHgPh showed that this unexpected reaction proceeded via two steps:condensation and symmetrization. 3e (R=Et, M=Mo) belongs to triclinic space group P-1, a=0.6333(1), b=0.7712(1), c=1.4204(4)nm; α=77.31(1), β=74.51(2), γ=68.72 (1)°; V=0.61714nm^3; Z=1; D_x=2.246g/cm^3; R=0.044.
出处
《化学学报》
SCIE
CAS
CSCD
北大核心
1992年第2期193-199,共7页
Acta Chimica Sinica
基金
国家自然科学基金
