摘要
魔芋中含有很多营养成分,其中有效成分是葡甘露聚糖(KGM),是理想的膳食纤维。葡甘露聚糖具有独特的性质和多方面的保健功能,可制成各种类型的食品。本试验以魔芋培养物为材料,采用二因素三水平试验设计,悬浮培养后采用分光光度计法测定葡甘露聚糖的含量,通过分析比较得出高KGM的最优组合。结果表明:光照条件下组培的中型魔芋的葡甘露聚糖含量最多,为3.3113 mg·mL^-1。
Amorphophallus contains many nutrients,and the active ingredient was glucomannan,which is an ideal dietary fiber.Glucomannan has unique properties and wide range of health functions,and could be made into various types of food.The test used Amorphophallus culture for the material and adopted two factors and three leavls experimental design,after the suspension culture determining the glucomannan from konjac by spectrophotometer.Then it could make the optimal combination by comparing the size of materials and test processing.The results showed that,the content of Amorphophallus glutcomannan in medium was the most in illumination by tissue culture,and the content was 3.3113 mg·mL^-1.
作者
付洪冰
FU Hong-bing(Xi′an University,Xi′an 710065,China)
出处
《黑龙江农业科学》
2020年第7期84-86,共3页
Heilongjiang Agricultural Sciences
基金
陕西省自然科学基础研究计划项目(2018JM3036)
西安市科技计划创新基金文理专项(CXY1352WL15)。
