摘要
为有效阻挡烟气,空气幕倾角角度必须大于零度。以公式说明了空气幕可以阻挡烟气的条件。某大厦50 m以上（13-22 F）疏散楼梯前室及合用前室入口处设置两台气幕机。通过CFD模型模拟计算空气幕保护下疏散楼梯前室及其附近的火灾烟气扩散-流动过程,火源最大功率为1.15 MW,火灾增长系数为0.08 kW/s2。机械排烟排风量取6 500 m3/h,空气幕出口风速为11 m/s,最大流量为2 350 m3/h。模拟结果120 s后烟气开始进入前室。将排烟量增加到12 500 m3/h,则烟气不会进入防烟前室。
The obliquity of air curtain mast bigger than 0° to hold back the smoke effectively. The condition under what the air curtain can hold back the smoke was explained by formula. Two air curtain machines were set if the part of building is higher than 50 m（form 13th to 22nd Floor） at the entrance of protected stairway atria and common atria. The smoke propagation was simulated under the protection of air curtain in and near the protected stairway. The biggest Heat Release Rate is 1.15 MW, the fire intensity coefficient was 0.08 kW/ s. The mechanical smoke exhaust system vented smoke 6 500 m3 every hour. 2 350 m^3/h of air passed through and the wind speed is 11 m/s at exit of air curtain. The simulation result shown that the smoke entered atria after 120 s. The smoke will not enter the atria if increase the smoke vent to 12 500 m^3/h.
出处
《消防科学与技术》
CAS
北大核心
2009年第8期596-599,共4页
Fire Science and Technology
基金
南京工业大学引进人才启动基金项目"火灾中风幕和水幕的作用机理与耦合作用研究"
关键词
空气幕
排烟
楼梯间
模拟计算
air curtain
smoke exhaust
staircase
simulation
