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FeCl_3和Fe_2Cl_6与KCl反应的热力学研究 被引量:2

Thermodynamic Study on the Reaction of FeCl3 and Fe2Cl6 with KCl
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摘要 用骤冷法研究FeCl3和Fe2Cl6与KCl的反应热力学,结果显示,在温度(638—788)K和压力(0.0011—0.0064)MPa范围内,KFeCl4是唯一气态配合物产物。反应(1/2)Fe2Cl6(g)+KCl(s)=KFeCl4(g)的热力学函数是△H^θm(298.15,KFeCl4,g)=(19.6±2.0)kJ·mol^-1,△S^θm(298.15,KFeCl4,g)=(-8.5±3.0)J·mol^-1·K^-1;反应FeCl3(g)+KCl(s)=KFeCl4(g)的热力学函数是△H^θm(298.15,KFeCl4,g)=(-56.9±2.0)kJ·mol^-1,△S^θm(298.15,KFeCl4,g)=(17.4±3.0)J·mol^-1·K^-1。 Thermodynamic properties of the vapour complex KFeCl4 have been studied by equilibrated quenching experiments. The results for the KCl-Fe2Cl6 and KCl-FeCl3 systems show that the KFeCl4 complex is the sole predominant vapour complex roughly at the temperature of (638-788) K and under pressure of (0. 001 1-0.0064) MPa. The results show ΔHm (298. 15, KFeCl4, g) = (19. 6 + 2. 0) kJ · mol-1 and ΔSm (298. 15, KFeCl4 , g) = -(8. 5 ± 3. 0) J · mol-1 · K-1 for the reaction (1/2)Fe2Cl6 (g) + KCl(s) = KFeCl4(g); ΔHm (298. 15, KFeCl4, g) =(-56. 9 ±2. 0) kJ · mol-1 and ΔSm (298. 15, KFeCl4, g) = (17. 4 + 3. 0) J · mol-1 · K-1 for the reaction FeCl3 (g) +KCl(s) =KFeCl4 (g).
机构地区 东北大学理学院
出处 《科学技术与工程》 2004年第12期1003-1005,1012,共4页 Science Technology and Engineering
基金 国家自然科学基金(50274027)资助
关键词 KFeCl4 FECL3 Fe2Cl6 气态配合物 骤冷法 <Keyword>KFeCl4 FeCl3 Fe2Cl6 vapour complex quenching
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